2(pi)f = m
Derived from:
E = mc^2
E = hf
Therefore, hf = mc^2
To simplify and avoid precision/rounding errors, we adopt natural units.
In units where c=1 and h_bar=1:
h_bar = h / 2(pi) (reduced Planck constant)
Since h_bar = 1, h = 2(pi)
Substitute h=2(pi) and c=1 into hf = mc^2:
2(pi)f = m(1)^2
2(pi)f = m
In this system, energy also simplifies to E=m and E=2(pi)f